Forums:
Can anybody explain this difference between the behavior of bash and
ksh?
When reading the man page, I would expect both of them to have the
behavior exhibited by ksh.
Why does bash seem to treat "return" like a single level "break" in
this context?
The "echo "$AA" | while read" is important context. If I change it to
"for i in 0 1", return does as expected.
If it's any help, changing "return" to "break 2" doesn't help. with
bash, it still gives "1 1 1 1"
while ksh still gives "1"
I wonder if it has anything to do with "while read" causing a subshell
to be created, and bash getting confused about the "return" inside of
a subshell. If so, it's a bug in bash that ksh gets right, so it
ought to be fixable.
ADVthanksANCE
Rick
----------- example of strange behavior below -----------
:~$ cat /tmp/testit
function strange {
for j in 0 1 2 3
do
AA=' 1
2'
echo "$AA" | while read i
do
echo "$i"
return
done
done
}
echo $(strange)
:~$ bash /tmp/testit
1 1 1 1
:~$ ksh /tmp/testit
1
----------- example of strange behavior above -----------

Bug in bash? different from ksh, at any rate...
On Sat, May 28, 2011 at 01:14:42AM -0700, Rick Thomas wrote:
>
> Can anybody explain this difference between the behavior of bash and
> ksh?
>
> When reading the man page, I would expect both of them to have the
> behavior exhibited by ksh.
> Why does bash seem to treat "return" like a single level "break" in
> this context?
>
> The "echo "$AA" | while read" is important context. If I change it
> to "for i in 0 1", return does as expected.
>
> If it's any help, changing "return" to "break 2" doesn't help. with
> bash, it still gives "1 1 1 1"
> while ksh still gives "1"
>
> I wonder if it has anything to do with "while read" causing a
> subshell to be created, and bash getting confused about the "return"
> inside of a subshell. If so, it's a bug in bash that ksh gets
> right, so it ought to be fixable.
I can't reproduce it:
$ cat strange.sh
function strange {
for j in 0 1 2 3
do
AA=' 1
2'
echo "$AA" | while read i
do
echo "$i"
return
done
done
}
echo $(strange)
$ bash ./strange.sh
1 1 1 1
$ ksh ./strange.sh
1 1 1 1
ii bash 4.1-3 The GNU Bourne Again SHell
ii mksh 39.3.20100725-1 MirBSD Korn Shell
Bug in bash? different from ksh, at any rate...
On May 28, 2011, at 2:47 AM, David Sastre wrote:
> On Sat, May 28, 2011 at 01:14:42AM -0700, Rick Thomas wrote:
>>
>> Can anybody explain this difference between the behavior of bash and
>> ksh?
>>
>> When reading the man page, I would expect both of them to have the
>> behavior exhibited by ksh.
>> Why does bash seem to treat "return" like a single level "break" in
>> this context?
>>
>> The "echo "$AA" | while read" is important context. If I change it
>> to "for i in 0 1", return does as expected.
>>
>> If it's any help, changing "return" to "break 2" doesn't help. with
>> bash, it still gives "1 1 1 1"
>> while ksh still gives "1"
>>
>> I wonder if it has anything to do with "while read" causing a
>> subshell to be created, and bash getting confused about the "return"
>> inside of a subshell. If so, it's a bug in bash that ksh gets
>> right, so it ought to be fixable.
>
> I can't reproduce it:
>
> $ cat strange.sh
> function strange {
> for j in 0 1 2 3
> do
> AA=' 1
> 2'
> echo "$AA" | while read i
> do
> echo "$i"
> return
> done
> done
> }
> echo $(strange)
>
> $ bash ./strange.sh
> 1 1 1 1
>
> $ ksh ./strange.sh
> 1 1 1 1
>
> ii bash 4.1-3 The GNU Bourne Again SHell
> ii mksh 39.3.20100725-1 MirBSD Korn Shell
>
Bug in bash? different from ksh, at any rate...
On 2011-05-28 10:14 +0200, Rick Thomas wrote:
> Can anybody explain this difference between the behavior of bash and
> ksh?
It depends on whether the shell starts a subshell for (compound)
commands in pipelines.
> When reading the man page, I would expect both of them to have the
> behavior exhibited by ksh.
> Why does bash seem to treat "return" like a single level "break" in
> this context?
>
> The "echo "$AA" | while read" is important context. If I change it to
> "for i in 0 1", return does as expected.
Actually, the pipeline is the most important. You can achieve the same
with a simpler script:
--88---
strange () {
for j in 0 1 2 3
do
: | { echo 1;return; }
done
}
echo $(strange)
--88---
> I wonder if it has anything to do with "while read" causing a subshell
> to be created,
Not exactly, it's the pipeline that causes creation of the subshell.
> and bash getting confused about the "return" inside of
> a subshell.
It does not get confused; as you can see, the subshell properly returns.
> If so, it's a bug in bash that ksh gets right, so it
> ought to be fixable.
There is no wrong or right here, since the susv3 specification is rather
vague:
,----
| Additionally, each command of a multi-command pipeline is in a subshell
| environment; as an extension, however, any or all commands in a pipeline
| may be executed in the current environment.
`----
So bash implements the default, while ksh implements the extension.
Having an option in bash to control the behavior would be nice, however.
See also the following blog entry:
http://backreference.org/2010/10/23/on-pipes-subshells-and-descriptors/.
Sven